Smurl from Python

If you thought the Web Service example on the about page of Smurl.name was complicated, here's a much simpler version. I use this code on my very own site for the email notifications which will contain long URLs.

Feel free to steal this code into your own projects:

from urllib import urlopen, quote

# variable 'url' is defined elsewhere
if len(url) > 80:
    url = urlopen('http://smurl.name/createSmurl?url=%s' % quote(url)).read()

Was that hard?

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