⬅︎ Back to isInt() JavaScript function
except when you want to consider "0" is an integer (which does)
function isInteger(s){ return (s%(parseInt(s)/Number(s)))===0; } is perfect solution (=
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except when you want to consider "0" is an integer (which does)
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function isInteger(s){ return (s%(parseInt(s)/Number(s)))===0; } is perfect solution (=