This blog post is 13 years old! Most likely, its content is outdated. Especially if it's technical.
I've just uploaded my second Python Cookbook
recipe. It's unfortunately not rocket science but it's application is potentially very useful. With this little function you can generate the next number in a string that contains at least one number.
The mini unittest is quite interesting perhaps:
$ python increment_strings.py
from 10dsc_0010.jpg to 10dsc_0011.jpg
from dsc_9.jpg to dsc_10.jpg
from 0000001.exe to 0000002.exe
from ref-04851 to ref-04852
- Previous:
- Playing with Reverend Bayesian 19 October 2005
- Next:
- Pandora - a great Internet radio 21 October 2005
- Related by Keyword:
- Python Cookbook arrived 05 April 2005
- Indent text like email clients do 11 November 2004
- PLEAC 31 October 2003
- Related by Text:
- jQuery and Highslide JS 08 January 2008
- I'm back! Peterbe.com has been renewed 05 June 2005
- Anti-McCain propaganda videos 12 August 2008
- Ever wondered how much $87 Billion is? 04 November 2003
- Guake, not Yakuake or Yeahconsole 23 January 2010
Looks to big for me... this will also work
import re
def increment(s):
....re.sub(r'\d+(?=[^\d]*$)', lambda m: str(int(m.group())+1).zfill(len(m.group())), s)
It's also faster. If you think it's too complex you can break it up.
slightly more readable version:
last_number = re.compile(r'\d+(?=[^\d]*$)')
def increment(string):
....def increment_number(match):
........num_str = match.group(1)
........str( int(num_str) + 1).zfill( len(num_str) )
....return last_number.sub(increment_number, string)